What is the range of values and the percentage uncertainty of of the volume
measurement (10.05±0.08)mL

The vehicle traveling in the opposing direction travels the following distance in the same amount of time: 200/9 (2.5) equals 99.38 meters.   The safe separation between the two vehicles is therefore: 129.38 + 99.38 = 228.76 meters.

To obtain the velocity function, we must calculate the integral of the acceleration function:

V ( t ) = ∫ a ( t ) d t V ( t ) = ∫ 3 d t = 3 t + c 1

To find the integral's constant, we use our initial conditions as a guide. As of now

t = 0

The speed is 80 km per hour.

80 km/h is equal to (80)(1000)/3600, or 200/9 meters per second.

V ( 0 ) = 3 ( 0 ) + c 1

200/ 9 = 0 + c 1

c 1 = 200/ 9

The distance the vehicle travels in

the number of seconds required to travel the same distance as the truck plus 30 meters (15 meters in front of and 15 meters behind the truck).

The distance covered by the vehicle is

In the same number of seconds, 200/9 t.

This is the amount of time it takes for the car to overtake and pass the truck.

15 metres.

To do this, the automobile travels a distance of:

S ( t ) = 3 /2 ( 20 ) + 200/ 9 ( 2 5 ) = 129.38 meters

The vehicle traveling in the opposing direction travels the following distance in the same amount of time:

99.38 meters is equal to 200/9 ( 2 5).

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Answer:

See below

Explanation:

acceleration = change in velocity / change in time

  Or      F = m * a

      So the first one   Accel = 40 m/s / 20 s = 2 m/s^2

   Or    100 N = 50 * a     A = 2 m/s^2       Same answer two different ways...

The others are similar ......

Vector values like displacement are aware of their direction. Distance and other scalar quantities are directionless. The different directions of motion can be disregarded when calculating the total distance traveled.

While distance and displacement appear to signify the same thing, they actually have very different definitions and meanings.

A scalar quantity known as distance measures "how much ground an object has traversed" while moving.

An object's total change in position is referred to as displacement, a vector variable that measures "how far out of place an object is."

Think about the motion shown in the following diagram as a way to test your grasp of this distinction. Walking 4 meters east, 2 meters south, 4 meters west, and then 2 meters north is a physics teacher.

The physics instructor has walked 12 meters in total, yet her displacement is 0 meters. She has "covered 12 meters of ground" (distance = 12 m) during the course of her move. However, when she has done moving, she is not "out of position"; that is, her motion has not caused any displacement (displacement = 0 m). Being a vector quantity, displacement must pay attention to direction.

In the same way as the 2 meters south cancels the 2 meters north, the 4 meters east cancels the 4 meters west. Vector values like displacement are aware of their direction. Distance and other scalar quantities are directionless. The different directions of motion of the physics teachers can be disregarded in calculating the overall distance traveled.

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The de Broglie wavelength of a proton in a linear accelerator is 122 pm. A photon's de Broglie wavelength is twice that of an electron.

The rate of The electron is then defined as E 10 (b) = 10-2 (c) Pe=100 ca) Pt = 10 mee. The wavelength of a particle or matter can be calculated using the formula below. Thus, when the microscope is set to 100 keV, the wavelength of electrons is calculated to be 3.88 pm, 2.74 pm at 200 keV, and 2.24 pm at 300 keV. A photon's frequency is defined as the number of wavelengths it travels per second. A photon, unlike an electromagnetic wave, cannot be colored. A photon, on the other hand, will correspond to light of a specific color.

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Answer:

See below

Explanation:

P1V1/T1 = P2V2/T2      IF  T1 = T2

Then

P1V1 = P2V2       P2 = 1/2 P1

P1V1 = 1/2 P1 V2        DIVIDE BOTH SIDES BY P1

V1 = 1/2 V2        MULTIPLY BOTH SIDES BY 2

2V1 = V2           OR     V2 = 2 V1     THE NEW VOLUME IS TWICE ORIGINAL

solution given there

The momentum of an object can be calculated with the formula below:

Where p is the momentum, m is the mass and v is the velocity.

The mass of the bus is greater than the mass of the car.

So, if they have the same velocity, the momentum of the bus will be greater.

Correct option: a.

The distance that separates the charges is 0.7 m.

The distance between the charges is determined by applying Coulomb's law of electrostatic force as shown below.

F = kq₁q₂/r²

where;

r² = kq₁q₂/F

r² = (9 x 10⁹ x 8 x 10⁻⁴ x 3 x 10⁻⁴) / (4.4 x 10³)

r² = 0.49

r = √0.49

r = 0.7 m

Thus, the distance that separates the charges is 0.7 m.

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The magnitude of the car's acceleration is 1.1 m/[tex]s^{2}[/tex].

Use this formula of acceleration, [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as

[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as, Here, initial velocity is zero.

a =  [tex]v^{2}[/tex] / 2s

v = velocity

s = distance

a = acceleration

Put the values in this formula, a =  [tex]v^{2}[/tex] / 2s

a = 15 × 15 / 2 × 100

a = 1.125 m/[tex]s^{2}[/tex]

Hence, the magnitude of the car's acceleration is 1.125 m/[tex]s^{2}[/tex].

Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].

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Using concepts of acceleration, velocity and position, it is found that:

A. The instantaneous velocity in 15 seconds is of -147 m/s².

B. The average velocity during this interval is of -9.8 m/s.

Cc. The distance fallen during this time is of 1102.5 meters.

The velocity after t seconds is given by the following equation:

v(t) = v(0) + at.

In which:

In the context of this problem, the values of these parameters are given as follows:

Then the velocity equation is given as follows:

v(t) = -9.8t.

In 15 seconds, the instantaneous velocity is given as follows:

v(15) = -9.8(15) = -147 m/s².

The average velocity during this interval is of given by the change in velocity divided by the change in time, hence:

Average velocity = (-147 - 0)/(15 - 0) = -9.8 m/s.

The position function is the integral of the velocity function, hence:

s(t) = -4.9t². (integral of -9.8t = -9.8t²/2 = -4.9t²).

The distance fallen in 15 seconds is:

s(t) = -4.9(15)² = -1102.5 (1102.5 meters fallen).

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The average acceleration of the helicopter, given that it changes its velocity from 22.0 m/s to 10.0 m/s is –1.5 m/s²

We understood that acceleration is defined as the change in velocity with time i.e

a = (v – u) / t

With the above formula, we can determine the average acceleration of the helicopter. Details below

The following data were obtained from the question:

a = (10 – 22) / 8

a = –12 / 8

a = –1.5 m/s²

Thus, we can conclude that the average acceleration is –1.5 m/s²

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If 10 light rays shined on a mirror than the 10 light rays light will converge or diverge.

A mirror is a wave reflector. Light consists of waves, and light waves reflect from the flat surface of a mirror.

There are two types of mirror concave and convex.

When parallel light beams strike a concave mirror, all of the rays that are reflected meet at the same location (focus). A concave mirror is also known as a converging mirror as a result.

Parallel light beams that strike a convex mirror's surface and are reflected appear to meet (diverge) at a single location, although they do not. so convex mirror is defined as a diverging mirror as a result.

So, rays of light will get converged or diverged.

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Answer:

its upto your mind and magic

Explanation:

Spring A will stretch more than spring B if same mass is hanged from both of them because the value of Ka is less than that of Kb.

According to hook's law, for a spring,

F = -Kx

where,

F is applied force on the spring,

x is the extension or compression in string,

K is the constant of proportionality known as spring constant,

The value of spring constant tells us about the stiffness of the spring,

According to the situation,

Ka = 30g/cm

Kb = 50g/cm

So, the answer is option B,

As we can see, the value of Kb is more than Ka so, we can say that the spring B is more stiff than spring A,

So, if same mass is hanged from the spring A and Spring B, the spring A will stretch more.

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The initial velocity of the projectile, Vo is 25√5 m/s.

What is initial velocity?

initial velocity is the velocity at time interval t=0 and it's representative as u.

It is velocity which the motion start.

Sol-as per the question

Sx=400 Vx=Vo cos 37°=4/5Vo

Sy= -100 Vy=Vo sin 37° 3/5Vo ay=-10 m/s^2

Let the time of flight be t

Sx=u^xt +1/2axt^2

=>400= 4/5Vot----------(eq1)

Sy=uyt +1/2 ay t^2

=>-100=3/5 Vot -5t^2-----(eq2)

By solving this we are get-

Vo=25√5 m/s

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The diameter of the copper wire if its resistance is to be the same as that of an equal length of aluminum wire with diameter 1.94 mm is 1.568mm

The obstruction to current flow in an electrical circuit is measured by resistance. The Greek letter omega Ω represents resistance, which is measured in ohms.

The term "resistivity" refers to a quality that quantifies how much an object resists having current flow through it. It is a feature of the material itself, independent of the size or form of the sample, and is typically temperature dependent, though it could also be pressure-dependent.

by formula we have ;

R=ρL/A =ρL/πd²/4

where

R = resistance

ρ= resistivity

L = length ; and

A = area of cross section = πd²/4

we know that,

ρ₁ of aluminum = 2.63×10⁻⁸Ωm ; d₁ is diameter of aluminum

ρ₂ of copper=1.72×10⁻⁸Ωm ; d₂ is diameter of copper

given: L of copper= L of aluminum

also, R of copper= R of aluminum

on cancelling the equal terms we get,

ρ₁/d₁²=ρ₂/d₂²

here d₂=d₁[tex]\sqrt\frac{resistivity of copper}{resistivity of aluminum}[/tex]

d₂=1.94[tex]\sqrt \frac{1.72}{2.63}[/tex]

d₂=1.568mm

Hence the diameter of copper wire is 1.568mm

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The defining character of a main sequence star is the fusing of hydrogen into helium in its core.

The main sequence is actually a stage in the life cycle of any star. At first, stars start out as clouds of dust. These cluster of dust then come together under the influence of gravity. If the cluster forms a small body, let's say 0.08 times the mass of our sun, it cannot undergo nuclear fusion, so they just become brown dwarfs. If the body formed is big enough, the resulting star gets hotter until temperatures become sufficient enough for hydrogen fusion to occur. This marks the beginning of the main sequence.

The size of the star determines how long the star will stay in its main sequence. Smaller stars are cooler, and burn through their hydrogen fuel slower, so they are able to stay in the main sequence longer, compared to higher mass stars. During the main sequence, the star generates lots of energy through nuclear fusion. This energy counteracts the force of gravity, keeping the star stable and preventing collapse.

An example of a main sequence star is the sun.

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A mass of can 0.11 kg rests on a fence post 1.7 m high. a 0.0020 kg bullet is fired horizontally at a can. it hits the can at 900 m/s, passes through it, and emerges at 720 m/s.

when the can hits the ground, it is 1.93 m away from the fence post.

for vertical fall,

d = 0.5*g*t^2

1.7 = 0.5*9.8*t^2

t = 0.589 s

use conservation of momentum to calculate the initial horizontal velocity to tin

mb*vbi = mb*vbf + mt*vt

2*10^-3*900 = 2*10^-3*720 + 0.11*vt

vt = 3.273 m/s

horizontal distance = vt*time

= 3.273 m/s * 0.589 s

= 1.93 m

Answer= 1.93 m

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The total tangential speed = 3.56 m/s

, r =2 m ,

t =44sw

=17rpm = 17*2*3.14/60

= 1.7793 rad/swo =

01) from rotational kinematic equation

w =wo+t1.7793 =0 + *44 =0.0404 rad/s^2

(2) from rotationla kinematic equation

w^2 -wo^2 = 21.7793*1.7793

= (2*0.0404*)=39.18 rad

3) v =rw =2*1.7793

tangential speed = 3.56 m/s

What is average angular acceleration?

A spinning object's change in angular velocity per unit of time is expressed quantitatively as angular acceleration, also known as rotational acceleration. It is a vector quantity with either one of two predetermined directions or senses and a magnitude component.

The formula for average angular acceleration is: a = change in velocity divided by change in time. a=(w2−w1)/(t2−t1) a = ( w 2 − w 1 ) / ( t 2 − t 1 ) . w2 represents the final velocity measured in radians per second. w1 represents the initial velocity measured in radians per second.

Therefore, tangential speed = 3.56 m/s

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The forces provided by the support will have to increase proportionally to the weight or force of the painter acting downward.

Balanced forces are forces that are equal but oppositely directed in their line of action.

When forces are balanced, there is no net movement of the object that the forces are acting upon.

The uniform plank is balanced by the supports.

When the painter stands on the plank, the force of gravity or the weight of the painter acts downwards.

In order for the forces to be balanced, the forces provided by the support increase according to the third law of motion which states that action and reaction are equal and opposite.

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The magnitude of the larger of the two individual forces. is 120.5N.

Solution:

x + y = 343

x - y = 177

2x = 520

x = 222.5 N

y = 343 N - 222.5 N = 120.5N.

The resultant force of two forces of equal magnitude is equal to one of the two vectors. In physics, the magnitude of a force is the sum of all forces acting on an object. If all forces act in the same direction, the force magnitude increases. When forces act on an object in different directions, the force magnitude decreases. If one force is stronger than the other, the force will move to the smaller side but the acceleration will be slower. So the result is the difference between the two forces.

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The velocity of the bird can be obtained as  6.38 m/s.

Let us recall that the acceleration is the rate at which the velocity is changed. In this case, we are told that; a bird flying 3.45 m / s directly north feels a wind directly East that accelerates at 0.558 m / S^2. Having seen the question we can pick the following parameters out from the question;

Initial velocity u = 3.45 m / s

Acceleration a = 0.558 m / S^2

Time taken =  5.25 s

Given that;

v = u + at

v = final velocity

u = initial velocity

a = acceleration

t = time taken

v = 3.45 + (0.558  *  5.25)

v = 6.38 m/s

We can see that as the bird tends to be flying as we can see in the question that have been shown above that the final velocity that it can have after 5.25 seconds is 6.38 m/s.

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a) The smaller resistance (R₁) is 4.

b) The larger resistance (R₂) is 12.

When resistors are connected in parallel, the supply current is equal to the sum of the currents passing through each one of them. The total current flowing through the branches of a parallel circuit is the supply current. Resistor parallel connections have the same potential difference.

Given,

R₁ + R₂ = 16,

R₂ = 16 - R₁

[tex]\frac{R_{1} R_{2} }{R_{1}+R_{2} }[/tex] [tex]= 3[/tex],

This statement can be written as,

[tex]\frac{1}{R_{1} } +\frac{1}{R_{2} } =\frac{1}{3}[/tex]

Substitute [tex]R_{2}[/tex] value in above equation,

[tex]\frac{1}{R_{1} } +\frac{1}{16-R_{1} } =\frac{1}{3}\\\\\frac{16-R_{1} +R_{1} }{R_{1}(16-R_{1}) } =\frac{1}{3}\\\\\frac{16}{R_{1(16-R_{1}) } } =\frac{1}{3} \\\\[/tex]

48 = R₁(16 - R₁)
16R₁ - R₁² = 48

- R₁²+ 16R₁ - 48 = 0
Multiply both sides by (-1).

R₁²- 16R₁ + 48 = 0

R₁² - (12 + 4)R₁ + 48 = 0

R₁ (R₁ - 12) - 4 (R₁ - 12) = 0

(R₁ - 4)(R₁ - 12) = 0
If R₁ = 4 then R₂ = 12 and if R₁ = 12 then R₂ = 4.
Therefore, it can be said that the smaller resistance is 4 and larger resistance is 12.

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The side the girl is sitting on will once tilt down.

The seesaw's left and right sides' opposing torques are balanced by the torque acting on the left side. The force will act on the seesaw itself at either the right or left side of the seesaw's center of gravity.

Formula: The expression for the amount of torque operating on a body is

torque =r F

where; r=position vector and F= force

if the force is applied at a right angle to the direction of r and the body is at a distance r from the pivot.

The seesaw's length is assumed to be l, and its left side's mass is assumed to be greater than its right side's mass.

[tex]m_{L}[/tex] > [tex]m_{R}[/tex]

Let the weight of the hefty body be [tex]M[/tex], and the mass of the girl be [tex]m[/tex].

The seesaw's left and right side rods' centers of gravity will be positioned [tex]\frac{l}{4}[/tex] of an inch apart from the center (or pivot). The girl and body are initially positioned [tex]\frac{l}{2}[/tex] apart from the pivot. as a result, initially

torque of left side= torque of right side

([tex]\frac{l}{4}[/tex])[tex]m_{L}[/tex][tex]g[/tex]+([tex]\frac{l}{2}[/tex])[tex]mg[/tex]=([tex]\frac{l}{4}[/tex])[tex]m_{R}[/tex][tex]g[/tex]+([tex]\frac{l}{2}[/tex])[tex]Mg[/tex]

we get,

[tex]\frac{m_{L} -m_{R} }{2}[/tex]= [tex]M-m[/tex]

Asking the body and the girl to move ([tex]\frac{l}{4}[/tex]) closer to the pivot will result in the following calculation of the net torque:

net torque= torque of left - torque of right

The seesaw is tilted to the left when we believe that the torque is greater on the left side.

τnet=[tex]\frac{l}{4} m_{L}[/tex][tex]g[/tex]+[tex]\frac{l}{4}[/tex][tex]mg[/tex]−[tex]\frac{l}{4} m_{R}[/tex][tex]g[/tex]−[tex]\frac{l}{4}[/tex][tex]Mg[/tex]

We obtain the following values by replacing the value of [tex]m_{L} -m_{R}[/tex] in terms of [tex]m[/tex] and [tex]M[/tex]

therefore,

 τnet=[tex]lg(\frac{M-m}{4} )[/tex]

Our presumption that the left side will tilt because M is heavy and m is tiny is valid since the torque on the left side will predominate.

The girl will again be sitting on the side that is tilting downward because she was previously sat on the left.

REMARK: We would have discovered negative net talk if we had thought that the right hand side was tilting or had more torque. As a result, in such scenario, we would have discovered that the left side tilts, contrary to what we had assumed. Both strategies are thus appropriate. But it is important to avoid guessing at all costs while answering these questions because doing so reduces the likelihood of getting the correct response.

The force that can cause an object to rotate along an axis is measured as torque. An object acquires angular acceleration due to torque.

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In the psychology experiment in which Hakeem participates, UCS is click, UCR is blink and tear up, CS is blowing a puff of air, CR is thought of the puff of air and NS is the click before puff of air was introduced.

In psychology the abbreviations of the given terms are as follows:

Here the Unconditioned Response is the blinking and tearing up because he does that even though there is no puff of air. Since clicking provokes the Unconditioned Response, clicking is the Unconditioned Stimulus. The clicking is paired with puff of air for multiple times, that is why Unconditioned Response is stimulated. So the puff of air is the Conditioned Stimulus.

Therefore,

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The orange was at a height of 3.26 m above the ground.

The third equation of motion is

v² - u² = 2aS

Given is an orange dropped from a tree and had a velocity of 8 m/s just before it hits the ground.

We can write -

[v] = 8 m/s

[a] = 9.8 m/s²

[u] = 0 m/s

Using third equation of motion, we get -

v² - u² = 2aS

64 - 0 = 2 x 9.8 x S

64 = 19.6 x S

S = 3.26 m

Therefore, the orange was at a height of 3.26 m above the ground.

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The likelihood that this star is not "venerable," or old, is low; but, we would need more details, particularly the star's spectral class, to be certain.

The relationship between the absolute magnitude M and the apparent magnitude m and luminosity distance DL is as follows:

M = m 5log10DL10 pc

The distance of 100 pc in this instance provides us a fairly straightforward relationship:

M=m−5=−1.0

Let's first calculate the star's luminosity in relation to the Sun's luminosity to understand why. This star is 5.7 magnitudes brighter than the Sun, which has an absolute magnitude of +4.7. Using the traditional scale where 5 magnitude equal a brightness factor of 100: LL=100(5.7)/5=190.5 where the subscript denotes the Sun.

Our star therefore has 200 times the brightness of the Sun. Depending on the spectral class, we might determine whether this star was a hot main sequence star or a low-temperature red giant. It's likely to be the latter if we were to attempt a guess. Smaller stars have not had the time to develop into red giants during the existence of our galaxy.

Larger star than the Sun will go through the red giant phase of their evolution much more quickly. In just 40 million years, even our Sun will increase from 100 to 2,000 times its current brilliance.

Therefore, if a red giant is visible to us at only 200 times the solar luminosity, we would have to observe it very quickly in cosmic time.

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