The employees at a baseball bat factory need to make 350,000 bats in 6 months. They make 2,750 bats each day and work 127 days in the 6 months. Do the employees make enough bats?

The value of x in the given figure is 10.

In the given triangle,

∠ADC = ∠BDC =  90°

Hence the triangles ΔACD and ΔBCD are right-angle triangles. Thus we can apply Pythagoras' theorem in both triangles.

So in ΔACD,

CB² = BD² + DC²

And in ΔBCD,

CA² = AD²+ DC²

But, CA = 15 and CB = x + 5

So, (x + 5)² = BD² + DC²

15² = AD² + DC²

⇒225 = AD² + DC²

Here, BD = AD as given in the figure

Replacing BD with AD in the first equation we get,

(x + 5)² = AD² + DC²

Now, equate the values of AD² + DC² to obtain the value of x,

(x + 5)² = 225

⇒ x² + 25 + 10x = 225

⇒ x² + 10x - 200 = 0

⇒ x² + 20x - 10x - 200 = 0

⇒x(x + 20) - 10(x + 20) = 0

⇒(x + 20)(x - 10) = 0

Thus x = -20, 10

Hence the value of x is 10.

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The option for 6-pack of student tickets will be of lesser cost than that of individual cost.

Multiplication is a way of finding the product of two or more numbers. It is one of the basic mathematical operations, that we use in our day to day life.

Given, total number of students= 6

Cost of individual student ticket= $21.50

Therefore, total cost of buying tickets to an adventure day= $(6×21.5)= $129.00

Now, cost of 6-pack of student tickets= $126.00

Thus by comparing the two costs, we can see that the lesser option between the two is the 6-pack of student tickets by $(129-126)= $3

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Answer:

Step-by-step explanation:

ewerwerer

Answer:

A , B, D, F

Step-by-step explanation:

A) ∠1 ≅ ∠ 4    {Vertically opposite angles are congruent}

B) m∠2 + ∠4 + ∠6 = 180°    {Straight line angles}

    ∠6 ≅ ∠3

⇒ ∠2 + ∠4 + ∠3 = 180°

D) ∠2 + ∠3 + ∠4 = 180°   {Straight line angles}

f) ∠2 + ∠3 = ∠5 + ∠6   {Vertically opposite angles}

Based on the given figures, the line of reflection will be c. Reflection across x-axis.

If it looks like the line of reflection is a horizontal line as is the case here, the way to find the line of reflection is by finding the midway point between corresponding points on the graph.

For instance, use the coordinates of D and D' and C and C'.

The coordinates of D and D' are:

D = (-1, 1)

D' = (- 1, -1)

The Midpoint can be found to be:

= ( (x₁ + x₂) / 2, (y₁ + y₂) / 2)

= ( (-1 + (-1)) / 2), ( (1 + (-1)) / 2

= (-1, 0)

The coordinates of C and C' are:

C = (4, 1)

C' = (4, -1)

The Midpoint can be found to be:

= ( (x₁ + x₂) / 2, (y₁ + y₂) / 2)

= ( (4 + 4) / 2), ( (1 - (-1)) / 2

= (4, 0)

The line of reflection is therefore the x-axis because the value of y is 0 and the x = axis is the line that crosses y at 0.

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The equation in slope-intercept form of the line passing through the given points is,  y = (-1/2)x + 1

A table containing values of x and y is given:

x           y

-2          2

0           1

2           0

4           -1

So the points on the line are:

(-2,2), (0,1), (2,0) and (4,-1)

The equation in slope-intercept form of a line is,

   y = mx + c,

where m is the slope of the line and c, the y-intercept of the line.

So we need to find the slope and the y-intercept of the line from the given table values.

Let (x₁, y₁) = (-2,2) and (x₂, y₂) = (0,1).

Then slope of the line, m = (y₂-y₁)/(x₂-x₁)

                                           = (1-2)/(0- -2)

                                           = -1/2

The y-intercept of a line is the y-co-ordinate of the point which intersect the y-axis. I.e., it is the y-co-ordinate of the point at which x = 0.

From the table, when x = 0, y = 1.

Hence the y-intercept, c = 1.

So finally, the equation in slope-intercept form of the line is,

y = (-1/2)x + 1

The question is incomplete. Find the complete question below:

Find an equation in slope-intercept form of the line that passes through the given points.

x           y

-2          2

0           1

2           0

4           -1

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After solving the quadratic equation x² + 3x = 40 using the quadratic formula, (A)  x = –8, x = 5  

We can solve this quadratic formula by following a few steps.

The given equation is,

x² + 3x =40

Let's subtract 40 from both sides,

x² + 3x - 40 =40 - 40

Or, x² + 3x - 40 = 0

Now, we have to find a suitable pair of factors of -40 which is capable to generate +3 ( coefficient of x ).

The required pair is 8 and -5, and ( 8 - 5 ) = 3    

[ -40 = 8 × -5 ]

Therefore, x² + 3x - 40 = 0

Or, x² + ( 8 - 5 )x - 40 = 0

Or, x² + 8x - 5x - 40 = 0

Or, x ( x + 8 ) - 5 ( x + 8 ) = 0   [ taking x and 5  as common ]

Or, ( x + 8 ) ( x - 5 ) = 0            [ taking ( x + 8 ) as common ]

If the multiplication or product of two or more terms is zero, then we can write each term as zero.

               ( x + 8 ) = 0

               Or, x = -8        ( by subtracting 8 from both sides )

              ( x - 5 ) = 0

              Or, x = 5           ( by adding +5 with both sides )

Now, we can conclude that x = -8 and 5.    

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The zeros of the factored form of the equation is x = 1, 5, and -7.

Factorization is the method of breaking a number into smaller numbers that multiplied together will give that original form. Factorization is expressing a mathematical quantity in terms of multiples of smaller units of similar quantities.

We have been given the factored equation as; y=(x−1)(x−5)(x+7) that has zeros (or x-intercepts).

y=(x−1)(x−5)(x+7)

then the roots of the equation;

For (x−1)

x - 1 = 0

x = 1

For (x−5)

x - 5 = 0

x = 5

For (x+ 7)

x + 7 = 0

x = -7

Hence, The zeros of the factored form of the equation is x = 1, 5, and -7.

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The perimeter of the rectangular tennis court is 96.7 m

An equation shows the relationship between two or more numbers and variables.

Let x represent the length and y represent the width. A rectangular tennis court has an area of 528 m², hence:

Area = length * width

528 = xy

y = 528/x

If the length is decreased by 1 m and the width is increased by 1 m, the area of the tennis court is increased by 16 m². Hence:

new area = new length * new width

528 + 16 = (x - 1)(y + 1)

xy + x - y + 1 = 544

x(528/x) + x - 528/x + 1 = 544

528 + x - 528/x + 1 = 544

multiplying through by x:

528x + x² - 528 + x = 544x

x² -15x - 528 = 0

x = 31.67, hence y = 528/31.67 = 16.67

Perimeter = 2(x + y) = 2(31.67 + 16.67)

Perimeter = 96.7 m

The perimeter is 96.7 m

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Answer:

2021= 700cds  2020=750cds

Step-by-step explanation:

Puedes ver como indica en el lado izquierdo que la barra de cds de el 2021 esta en la mitad de 800 y 600 que es igual a 700 cds en 2021

Y en la parte del 2020 se ve que este en la mitad de 800 y 700 considerando el calculo anterior por lo que daría 750 cds en 2020

The general form of equation a) y = 2, b) x = -4.

Here the point A = (-4,2)

a) we have to find the equation parallel to the x-axis

As a line should be parallel to x axis so it must pass from y-axis. As the coordinate of A is (-4, 2) so by this we get y = 2 and x = -4.

But we have to put the value of x as 0 and y = 2 then only we get an equation of a line parallel to x-axis.

So y = 2

which is parallel to x-axis

b) equation of a line perpendicular to the x-axis.

As a line should be perpendicular to x-axis, so line should pass form the x-axis and not with the y-axis. As point A is (-4. 2), so we have to take the value of x = -4 and y = 0. So we get an equation.

x = -4 is the general equation.

Therefore the general equation a) y =2 and b) x =-4.

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Answer:

i believe the answer is the distributive property

You cannot replace a type of formatting inside a cell with a different type of formatting.

Your search string is treated as a pattern by the dialog box, which then returns all records that do. Consider the case where you have a datasheet (a table or a query result) with details on clients, vendors, goods, and order dates. The find operation returns all occurrences of "mar" when you perform a search, along with any additional entries that meet the pattern you supplied.

The dialog box doesn't scan the full database; it simply searches one table at a time. You can search the table that supports a form if the dialog box is opened from within one.

For some features provided by the Find and Replace dialog box the search and replace feature can't accept the following condition.

That a user cannot replace a type of formatting inside a cell with a different type of formatting.

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Answer:

x=24

y=58

Step-by-step explanation:

5x+20=6x-4

5x-6x=-20-4

-x=-24 /:(-1)

x=24

5×24+20+y-18=180

122+y=180

y=180-122

y=58

Answer:

A question you will ask the people in your sample.

Answer:

d  138

Step-by-step explanation:

<5 is vertical to <2, so they are congruent.

<2 is corresponding to the 138° angle, so they are congruent.

m<5 = m<2 = 138°

Answer: d  138

Answer:

58/9 = x

Step-by-step explanation:

3(x-5) + 2(3x-1) = 41

Expand:

(3x-15) + (6x-2) = 41

Simplify:

9x-17 = 41

9x = 58

x = 58/9

Hope that helps

Answer:

There is a linear relationship between costumes and fabric. The rate of change is 3 1/2 yards per costume.

Step-by-step explanation:

The second possible answer is correct,

3 and 1/2

brailiest would be appreciated :]

Answer:  The correct answer is B. There is a linear relationship between the number of costumes and fabric. The rate of change is 3.5 yards per costume.

Step-by-step explanation:

Divide the Fabric yards by the number of costumes:

7 / 2 = 3.5

14 / 4 = 3.5

21 / 6 = 3.5

28 / 8 = 3.5

Since they are all 3.5 yards per costume, the relationship is LINEAR

By solving equations, we can conclude that there are 30 oatmeals in the jar.

So, a number of oatmeals are in the jar.

The total number of cookies is 54.

From the equation:

Now, solve for 'x' as follows:

Number of oatmeals when "x = 6':

Therefore, by solving equations, we can conclude that there are 30 oatmeals in the jar.

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The Yes or No to for digit in the hundreds place is to the value of the digit in the thousands place are-

3a. 8,556 ; No ,    3b. 6,855 ; No ,  3c. 5,568 ; Yes     , 3d. 5,656 ; No

As per the place value system,

Thousand    Hundred    Tens    Ones

3a. 8,556

Thousand value of number = 8000

Hundred value of number = 500

1/10 × 8000

800 ≠ 500

No, the digit at hundreds place is not 1/10 of the digit at thousand place.

3b. 6,855

Thousand value of number = 6000

Hundred value of number = 800

1/10 × 6000

600 ≠ 800

No, the digit at hundreds place is not 1/10 of the digit at thousand place.

3c. 5,568

Thousand value of number = 5000

Hundred value of number = 500

1/10 × 5000

500 = 500

Yes, the digit at hundreds place is 1/10 of the digit at thousand place.

3d. 5,656

Thousand value of number = 5000

Hundred value of number = 600

1/10 × 5000

500 ≠ 600

No, the digit at hundreds place is not 1/10 of the digit at thousand place.

Thus, the condition of yes and no for the given number are obtained.

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The complete question is-

3. For items 3a-3d,

Choose yes or no to tell if the digit in the hundreds place is 1/10 the value of the digit in the thousand place.

thousands place.

3a. 8,556

3b. 6,855

3c. 5,568

3d. 5,656

Answer:

24 cans=72 people

1 people = 24÷72 cans

39 people = 24÷72×39 cans

=13 cans

The four consecutive integers in the question are; 51, 52, 53, 54

Let the four consecutive integers in the question be;

x, x + 1, x + 2 and 2(x + 4)

Now, we are told that the sum of these four consecutive integers is 264. Thus;

x + x + 1 + x + 2 + 2(x + 3) = 264

Expanding the bracket gives;

3x + 3 + 2x + 6 = 264

5x + 9 = 264

5x = 264 - 9

5x = 255

x = 255/5

x = 51

Thus;

Second integer = 51 + 1 = 52

Third integer = 51 + 2 = 53

Fourth Integer = 51 + 3 = 54

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Answer:

$27.00 is discounted from the price.

Step-by-step explanation:

60% means per hundred

60/100 when you divide by 100 you move the decimal 2 places to the left

.6 x 45 = 27

 A function is a relationship between inputs where each input is related to exactly one output.

The outputs are called the range

The range of the function:

R = {-1, 0, 3}

Option C is the correct answer.

 A function is a relationship between inputs where each input is related to exactly one output.

A function has an input and an output.

Example:

f(x) = x + 1

f(1) = 1 + 1 = 2

Input = domain = 1

Output = range = 2

We have,

Function:

y = x² - 1

The domain of a function = {-2, -1, 0, 1, 2 }

Let y = f(x)

x = -2, -1, 0, 1, 2.

f(-2) = 4 - 1 = 3

f(-1) = 1 - 1 = 0

f(0) = 0 - 1 = -1

f(1) = 1 - 1 = 0

f(2) = 4 - 1 = 3

Thus,

The range of the function:

R = {-1, 0, 3}

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