Here is a vertical algorithm that we can use to find 60.19 – 47.52.Which place value column(s) will require regrouping?Please see image below.

Here Is A Vertical Algorithm That We Can Use To Find 60.19 47.52.Which Place Value Column(s) Will Require

Answers

Answer 1

Regrouping happens when we need to "borrow" value from the higher order digits to perform a subtraction properly. This happens on the tenths, because we need to subtract 5 from 1, which we can't do normally. So we need to regroup from the ones and tens, in order to solve the problem. The correct answer is B.


Related Questions

What is Qualitative Data and what is the discreate and Continuous in qualitative data?

Answers

Answer:

Qualitative data is the data that is not represented by numbers, for example, favorite food or country.

On the other hand, the quantitative data is represented by numbers and it is classified as discrete and continuous. The discrete data is the data that only can take specific values, for example, the number of people is always a whole number, there can't be 5.5 people. The continuous data is the data that can take decimal values, for example, the mass of an object can be 4.06 kg.

While solving an equation 2x^2+32=0 the answer calculated is x=+-4i I understand the +- means the answer can be positive or negative but what does the i mean

Answers

Answer:

Explanation:

Given:

[tex]\begin{gathered} 2x^2+32=0 \\ \text{The answer is x=}+-4i \end{gathered}[/tex]

To fully understand how we get the given answer, we simplify the equation first:

[tex]\begin{gathered} 2x^2+32=0 \\ \text{Simplify and rearrange} \\ 2x^2=-32 \\ x^2=-\frac{32}{2} \\ x^2=-16 \\ \end{gathered}[/tex]

Next, we apply the rule:

[tex]\begin{gathered} \text{For x}^2=f(a),\text{ the solutions are } \\ x=\sqrt[]{f(a)} \\ x=-\sqrt[]{f(a)} \end{gathered}[/tex]

So,

[tex]\begin{gathered} x^2=-16 \\ x=\sqrt[]{-16},x=-\sqrt[]{-16} \end{gathered}[/tex]

Then, we also apply the radical rule:

[tex]\begin{gathered} \sqrt[]{-a}=\sqrt[]{-1}\sqrt[]{a} \\ So, \\ x=\sqrt[]{-16} \\ =\sqrt[]{-1}\sqrt[]{16} \\ \text{Then, apply the imaginary number rule:} \\ \sqrt[]{-1}=i \\ \text{Hence,} \\ x=4i \end{gathered}[/tex]

For

[tex]\begin{gathered} x=-\sqrt[]{-16} \\ Use\text{ the same steps} \\ x=-4i \end{gathered}[/tex]

Therefore the x-values are: x=4i, x=-4i. The i on the answer means imaginary number. It is a number that, when squared, has a negative result.

For each relation, decide whether or not it is a function.

Answers

Relation 1: Yes, each input corresponds to only one output.

Relation 2: No, the input of -1 corresponds to two outputs: sun and moon.

Relation 3: Yes, each input corresponds to only one output.

Relation 4: Yes, each input corresponds to only one output.

Solve the following. List all possible possible solutions for the ambiguous case. #7

Answers

The sum of the interior angles of any triangle is always 180º:

[tex]A+B+C=180[/tex]

Use the equation above and the given data to find C:

[tex]\begin{gathered} C=180º-A-B \\ C=180º-38º-72º \\ C=70º \end{gathered}[/tex]

Law of sines:

[tex]\frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}[/tex]

Use the pair of ratios for a and b to solve a:

[tex]\begin{gathered} \frac{a}{sinA}=\frac{b}{sinB} \\ \\ a=sinA*\frac{b}{sinB} \\ \\ a=sin38º*\frac{12}{sin72º} \\ \\ a=7.8 \end{gathered}[/tex]

Use the pair of ratios for b and c to solve c:

[tex]\begin{gathered} \frac{c}{sinC}=\frac{b}{sinB} \\ \\ c=sinC*\frac{b}{sinB} \\ \\ c=sin70º*\frac{12}{sin72º} \\ \\ c=11.9 \end{gathered}[/tex]Thenm, the solution for the given triangle is:A=38ºB=72ºC=70ºa=7.8b=12c=11.9

8. Find the slope between (-5, 4) & (0,3). * O m = 1/5 O O m = -5 m = 5 O m = -1/5

Answers

We can determine the slope using the following expression:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Now, using the two points given, we have:

[tex]m=\frac{3-4}{0-(-5)}\Rightarrow m=-\frac{1}{5}[/tex]

From this, we have that the slope(m) equals -1/5.

while digging in his garden , will pushes a shovel into the ground at an 80 degree angle with 585 newtons of force . show the resolution of the force into its retangular components

Answers

Solution

Part a

Part b

For this case we can do this:

Fx= 585 N* cos 80= 101.58 N

Fy= 585N * sin 80= 576.11 N

Then the best answer is:

B. (102, 576) N

Graph the line that has an z-intercept of (-3,0) and a y-intercept of (0, - 5). What is the slope of this line?

Answers

Answer:

the slope is -5/3

Step-by-step explanation:

it is that because to find slope u do y2-y1/x2-x1

What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?

Answers

Answer:

slope = 5/4

Step-by-step explanation:

What is the slope of a line that passes the points (-1,4 ) and ( 3,9 ) ?

slope = change in y ÷ change in x

slope = (9-4) ÷ (3 - (-1))

slope = 5/4

What is the value of (–3 + 3i) + (–2 + 3i)?

Answers

Answer: -5+6i

Step-by-step explanation:

The figure shows a quarter circle and an equilateral triangle. What is thearea of the shaded part? Give your answer to 3 significant figures. (Take it= 3.14.)7 cm

Answers

Since the triangle is equilateral, all of its interior angles have a measure of 60º.

Substract the area of the triangle from the area of a circular sector with radius 7cm enclosed by an angle of 60º to find the area of the shaded region.

The area of an equilateral triangle with side length L is:

[tex]A=\frac{\sqrt[]{3}}{4}L^2[/tex]

The area of a circular sector of radius r enclosed by an angle of θ degrees is:

[tex]A=\frac{\theta}{360}\times\pi r^2[/tex]

Replace θ=60 and r=7cm to find the area of the circular sector:

[tex]A_c=\frac{60}{360}\times3.14\times(7\operatorname{cm})^2=25.643\ldots cm^2[/tex]

Replace L=7cm to find the area of the triangle:

[tex]A_T=\frac{\sqrt[]{3}}{4}\times(7\operatorname{cm})^2=21.2176\ldots cm^2[/tex]

Then, the area of the shaded region is:

[tex]\begin{gathered} A_C-A_T=25.6433\ldots cm^2-21.2176\ldots cm^2 \\ =4.4257\ldots cm^2 \\ \approx4.43\operatorname{cm}^2 \end{gathered}[/tex]

Therefore, the area of the shaded region to 3 significant figures, is:

[tex]4.43\operatorname{cm}^2[/tex]

Given the general form: F( x )= a(x^2)+bx+cConvert it to vertex form (also known as standard form) by putting the values for a,h and k into the correct boxes.F(x)=a(x-h)^2+kIdentify the vertex(x,y)General form: F( x )=1 x^2+6 x +-1 Vertex form: F( x )= Answer for part 1 and coordinate 1 (x- Answer for part 1 and coordinate 2 )^2 +Answer for part 1 and coordinate 3Vertex: (Answer for part 2 and coordinate 1,Answer for part 2 and coordinate 2)

Answers

[tex]\begin{gathered} Vertex\colon\: (-3,-10) \\ Vertex\: form\: equation\colon\: f(x)=(x+3)^2-10 \end{gathered}[/tex]

1) In order to convert from the standard version to the vertex form we'll need to find the vertex of that parabola:

[tex]f(x)=x^2+6x-1[/tex]

We can find the vertex, using these formulas:

[tex]\begin{gathered} x=h=-\frac{b}{2a}=\frac{-6}{2}=-3 \\ k=(-3)^2+6(-3)-1=9-18-1=9-19=-10 \\ V(-3,-10) \end{gathered}[/tex]

So this is the vertex of that parabola at point (-3,-10)

2) Now, note that the coefficient a = 1, and with the vertex, we can now rewrite that equation into the vertex form:

[tex]\begin{gathered} y=a(x-h)^2+k \\ y=(x-(-3))^2+(-10) \\ y=(x+3)^2-10 \end{gathered}[/tex]

Jamar finds some nickels and quarters in his change purse. How much money (in cents) does he have if he has 4 nickels and 11 quarters? How much money (in cents) does he have if he has n nickels and q quarters?

Answers

1 nickel is worth 5 cents and 1 quarter is worth 25 cents.

So, if he has 4 nickels, this is worth 4 times 5 cents and if he has 11 quarters, this is worth 11 times 25 cents.

Both are worth the sum of these, so:

[tex]4\cdot5+11\cdot25=20+275=295[/tex]

So, he has 295 cents.

If he has n nickels and q quarters, he has 5 times n plus 25 times q worth, so he has:

[tex]5n+25q[/tex]

What’s the correct answer answer asap for brainlist

Answers

Answer:

A. a chorus

Step-by-step explanation:

What is the scale factor of Figure B to Figure A?48.6B2510A1021.5A. O 6.25B.O 2.5C.0.16D. 0.4

Answers

As per given by the question,

There are given that two traingle, figure A and figure B.

Now,

The ratio of a dimension on figure B to the corresponding dimension on figure A is,

[tex]4\colon10=8.6\colon21.5=10\colon25[/tex]

So,

The scale factor is,

[tex]\begin{gathered} k=\frac{10}{4}=\frac{25}{10}=\frac{21.5}{8.6}=2.5 \\ \end{gathered}[/tex]

The scale factor of figure B on the figure A is 2.5.

Hence, the option B is correct.

1)EF=JHFEG = HJGXProve FEG = HJGStatement1) EF = JHReason1) given2)2) given3) Vertical angles are conguent3)4)4)Theorem

Answers

2.

[tex]\angle FEG\cong\angle HJG[/tex]

3.

[tex]\angle HGJ\cong\angle EGF[/tex]

If sin 0= -3/5 in quadrant 3, what is cos 0?

Answers

Given

[tex]sin\theta=-\frac{3}{4}[/tex]

Solution

Recall : SOHCAHTOA

The final answer

Option A

[tex]Cos\text{ }\theta=-\frac{4}{5}[/tex]

I need help with this practice,I will send you an additional pic that goes along with this problem Freya went to her local park to find 5 organisms/species She found 5 and wrote down the name of these organisms and the quantity of each she seen:Eastern gray squirrels/14 individualsWolf spiders/2 individualsPaper wasps/9 individualsBlack vulture/1 individualNorthern cardinals/7 individuals

Answers

ANSWER :

The answer is 5/33 or 0.15

EXPLANATION :

From the problem, we have a total of 5 number of species.

Using the given Biodiversity Index formula :

[tex]\frac{\text{ total number of species}}{\text{ total number of individuals}}=\frac{5}{14+2+9+1+7}=\frac{5}{33}\quad or\quad0.1515[/tex]

A shop repairs 4 types of electronic devices. The number of repairs of each device last week is shown in the bar graph below. Use this bar graph to answer the questions.

Answers

Answer:

a) Telephone; 2 repairs

b) 3 more repairs

c) computer, radio , and television = 3 types

Explanation:

From the bar graph we see that the least amount of repairs done to the telephones. How many r

The total cost, in dollars of a membership in a fitness center is given by the function c(m) = 40m +10, where m is the number of months a person is a member. In dollars, how much is the cost of a membership for 1 year?

Answers

The cost of a membership for 1 year is 490

How to determine the cost of a membership for 1 year?

The equation of the membership is given as

c(m) = 40m + 10

From the question, we understand that:

m represents the number of months

For the cost of a membership for 1 year, the number of months is 12

i.e. m = 12

Substitute the known values in the above equation

So, we have

c(12) = 40 * 12 + 10

Evaluate

c(12) = 490

Hence, the cost is 490

Read more about linear equation at

https://brainly.com/question/4074386

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In how many ways can a committee of 5 be chosen from 9 people given that Jones must be one of them?

Answers

There are 126 ways to choose a committee of five from a group of nine people using combinations; one of them must include JONES.

What do we mean by COMBINATIONS?Combinations are a mathematical method for calculating the number of alternative arrangements. In a collection of objects where the order of the selection is irrelevant. You are free to choose any combination of the available things.Mathematically it can be expressed as : nCr = n! / r!(n-r)!

So, we have a comiitte of 5 be chosen from 9 people and JONES must be one of them -

Using the rule of combinantion - nCr = n! / r!(n-r)!We have n = 9 and r= 59C5 = 9! / 5!(9-5)!C(9,5) = 3024/24C(9,5) = 126

Therefore, there are a total of 126 ways in which we can decide that JONES must be on it.

Know more about combinations here:

https://brainly.com/question/28065038

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use the two given points and calculate the slope.(6,4),(4,-1)

Answers

EXPLANATION:

Given;

We are given two points which are shown below;

[tex]\begin{gathered} (6,4) \\ (4,-1) \end{gathered}[/tex]

Required;

We are required to calculate the slope.

Step-by-step solution;

To calculate the slope given two points, we shall use the following formula;

[tex]\begin{gathered} Slope: \\ m=\frac{y_2-y_1}{x_2-x_1} \end{gathered}[/tex]

Where the variables are;

[tex]\begin{gathered} (x_1,y_1)=(6,4) \\ (x_2,y_2)=(4,-1) \end{gathered}[/tex]

We can now substitute these values and solve;

[tex]m=\frac{-1-4}{4-6}[/tex][tex]m=\frac{-5}{-2}[/tex][tex]m=\frac{5}{2}[/tex]

Therefore.

ANSWER:

[tex]m=\frac{5}{2}[/tex]

can somebody please help me with this question

Answers

Answer:

I don't really understand this but I think will be a great way to solve this so 123.00

Step-by-step explanation:

.

I'll send a picture! please answer fast!

Answers

Given data:

The given expression for the points is,

[tex]10w-3t+5[/tex]

Thus, the expression or

10. The product of 6 and a number when added to 5 is equal to 1 less than 9 times the number.

Answers

6x+5=9x-1
6x+4=9x
3x=4
X=4/3

Answer:

x = 2

Step-by-step explanation:

Hello!

Let the unknown number be x. The product of 6 and that number can be represented by 6x. And since we are adding 5, we can use 6x + 5 to represent that expression.

This equation is equal to the difference of 9x and 1, or 9x - 1.

Solve for x6x + 5 = 9x - 15 = 3x - 16 = 2x2 = x

The value of x is 2.

Select the correct answer. What is the solution to the equation? (x - 2)^1/2 + 4 = x A. -3 and -6 B. 3 and 6 C. -3 D. 6

Answers

Answer:

D.  x = 6

Step-by-step explanation:

Given equation:

[tex](x-2)^{\frac{1}{2}}+4=x[/tex]

Subtract 4 from both sides:

[tex]\implies (x-2)^{\frac{1}{2}}+4-4=x-4[/tex]

[tex]\implies (x-2)^{\frac{1}{2}}=x-4[/tex]

Square both sides:

[tex]\implies \left( (x-2)^{\frac{1}{2}}\right)^2=(x-4)^2[/tex]

[tex]\implies x-2=(x-4)^2[/tex]

Expand the brackets on the right side:

[tex]\implies x-2=(x-4)(x-4)[/tex]

[tex]\implies x-2=x^2-8x+16[/tex]

Subtract x from both sides:

[tex]\implies x-2-x=x^2-8x+16-x[/tex]

[tex]\implies -2=x^2-9x+16[/tex]

Add 2 to both sides:

[tex]\implies -2+2=x^2-9x+16+2[/tex]

[tex]\implies 0=x^2-9x+18[/tex]

[tex]\implies x^2-9x+18=0[/tex]

Factor the left side of the equation:

[tex]\implies x^2-6x-3x+18=0[/tex]

[tex]\implies x(x-6)-3(x-6)=0[/tex]

[tex]\implies (x-3)(x-6)=0[/tex]

Apply the zero-product property:

[tex]\implies x-3=0 \implies x=3[/tex]

[tex]\implies x-6=0\implies x=6[/tex]

Therefore, the solutions of the quadratic equation are:

[tex]x=3, \quad x=6[/tex]

Input both solutions into the original equation to check their validity:

[tex]\begin{aligned}x=3 \implies (3-2)^{\frac{1}{2}}+4&=3\\(1)^{\frac{1}{2}}+4&=3\\1+4&=3\\5&=3\end{aligned}[/tex]

[tex]\begin{aligned}x=6 \implies (6-2)^{\frac{1}{2}}+4&=6\\(4)^{\frac{1}{2}}+4&=6\\2+4&=6\\6&=6\end{aligned}[/tex]

Therefore, the only valid solution to the given equation is x = 6.

Answer:

The answer is D. 6

Step-by-step explanation:

Add both sides:

(x - 2)^1/2 + 4 + (-4) = x + (-4)

(x - 2)^1/2 = -4

Solve exponent:

(x - 2)^1/2 = x - 4

((x - 2)^1/2)^2 = (x - 4)^2

x − 2 = x^2 − 8x + 16

x − 2 − (x^2 − 8x + 16) = x^2 − 8x + 16 − (x^2 − 8x + 16)

−x^2 + 9x − 18 = 0

(−x + 3)(x − 6) = 0

−x + 3 = 0 or x − 6 = 0

x = 3 or x = 6

Check the answers: (Plug them in to see what will work.)

x = 3 (won't work)

x = 6 (does work)

Therefore,

x = 6

i need help with this problem

Answers

Answer:

whats the problme?

Step-by-step explanation:

Use the ALEKS calculator to write as a percentage.
31
32
Round your answer to the nearest tenth of a percent.
0%
X 5
?

Answers

Divide 31 into 32 and then multiply the result by 100 to get the percent:

[tex]\begin{gathered} \frac{31}{32}=0.96875 \\ \\ 0.96875*100=96.875 \end{gathered}[/tex]Then, to the nearest tenth of a percent the given fraction is 96.9%

Find the equation for the circle with a diameter whose endpoints are (8,17) and (4, - 15).

Answers

Answer:

Given that,

Circle with a diameter whose endpoints are (8,17) and (4, - 15).

To find the equation for the circle

we know that,

Equation of the circle is of the form,

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where r is the radius and (h,k) is the center of the circle.

If the end points of the diameter is given, then the equation of the circle is,

[tex](x-x1)(x-x2)+(y-y1)(y-y2)=0[/tex]

Substitute the points we get,

[tex](x-8)(x-4)+(y-17)(y+15)=0[/tex]

On simplifying this we get,

[tex]x^2-8x-4x+32+y^2-17y+15y-255=0[/tex][tex]x^2+y^2-12x-2y-223=0[/tex]

The tables of ordered pairs represent some points on the graphs of lines q and v. Line 9 Line v Х -9 -3 2. Х 0 10 у 0 18 33 у 10 8 3 Which system of equations is represented by lines q and v? F 21x - y = 9 5x + 6y = 40 G 3x - y = -27 x + 2y = 16 H 21x - y = 9 5x - 6y = 20 3 9x - y = -27 x + 2y = 8

Answers

One of the forms we can write the equation of a line is like this:

y - y1 = m(x - x1)

Where (x1, y1) is a point where the line passes through, and the value of m, the slope of a line is given by the following formula:

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Then, for the first line (line q), we can take the points (-9, 0) and (-3, 18), then we get:

[tex]mq=\frac{18-0}{-3-(-9)}=\frac{18}{-3+9}=\frac{18}{6}=3[/tex]

By replacing the value of the slope and the coordinates of the point (-9, 0), we get:

y - 0 = 3(x - (-9))

y = 3(x + 9)

y = 3x + 27

y - y = 3x + 27 - y

0 = 3x + 27 - y

-27 = 3x + 27 - 27 - y

-27 = 3x - y

For line v, we can take the points (-4, 10) and (0, 8), then we get:

[tex]mv=\frac{8-10}{0-(-4)}=\frac{-2}{4}=-\frac{1}{2}[/tex]

By taking -1/2 for the slope and the coordinates of the point (0,8), we gat:

y - 0 = -1/2(x - 8)

y = -1/2x + 4, multiplying both sides by 2:

2y = -x + 16

2y + x = -x + x + 16

2y + x = 16

Then, the system represented by the lines q and v is option G

Given the formula FV = P + Prt, what is the future value of a savings account that had an initial deposit of $7,900 earning 6.5% simple interest for 4 years?$10,074.23$9,954.00$9,376.85$10.756.43None of these choices are correct.

Answers

Step 1: Use the formula below to find the future value:

Fv = P + Prt

P = present value or initial deposit

r = rate in %

t = time in years

Step 2: List the given data

P = $7900

r = 6.5% = 0.065

t = 4 years

Step 3: Substitute the values of P, r and t to find the future value.

FV = P + Prt

= 7900 + 7900 x 0.065 x 4

= 7900 + 2054

= $9954.00

Stop 4: Final answer

Future value = $9954.00

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