A toy car can go 15 m/s at it max speed you play with it at it max speed for 30min before the battery dies how far did the car go

Answers

Answer 1

Given:

Speed of the toy car max speed = 15 m/s

Time taken before the battery dies = 30 minutes.

Let's find how far the car went.

To find the distance the car travelled, aply the formula:

[tex]\text{distance}=\text{speed}\times time[/tex]

Where:

Speed = 15 m/s

time = 30 min

Convert the speed to meters per hour

Convert the time to hour.

Where:

1 hour = 60 mins = 3600 seconds

Thus, we have:

• Speed in m/h:

[tex]\text{speed}=15\text{ m/s}\times3600=54000\text{ m/h}[/tex]

• Time in hour:

[tex]\text{Time}=\frac{30\min }{60\text{ min/h}}=0.5\text{ hour}[/tex]

To find the distance, we have:

[tex]\begin{gathered} \text{Distance = speed x time} \\ \\ \text{Distance = 5400 m/h }\times0.5=27000\text{ meters} \end{gathered}[/tex]

Therefore, the toy car travelled 27000 meters.

ANSWER:

27000 meters.


Related Questions

Downhill ski racing requires the racer to maintain the tuck position for over a minute while they are going extremely fast therefore the muscle fibers recruited must not fatigue easily or the scare could be severely injured which type of muscle fiber is predominantly recruited during downhill ski racing?

Answers

Answer:

slow twitch fibers

Explanation:

Slow twitch fibers can maintain a force for a longer period of time than fast twitch fibers

an athlete stretches a spring an extra 29.0 cm beyond its initial length. how much energy has he transferred to the spring, if the spring constant is 68.0 n/cm ?

Answers

If the spring is constant at 68.0 n/cm, the energy he has transferred to the spring is 2028 N.

Hooke's law, which asserts that, must be applied,

F = k x

The spring constant in N/cm is k.

The extension in centimeters is x.

By incorporating x = 35.7 cm and k = 56.8 N / c m, we obtain the force, which is equivalent to

F = 56.8 N/cm 35.7 cm = 2027.76 N

2028 N, rounded to the next whole value.

The spring's shape, which was created by coiling a metal wire into tight loops pressed up against one another, gives it elastic properties. When an external force is applied to a spring, a restoring force always acts in the direction of the spring's equilibrium state. The spring stores mechanical energy.

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According to Newton's
2nd law of motion, if you hit a baseball with a bat it will
• hurt your hand from the reaction force
O accelerate according to the applied force
• fly in a straight line
unless an outside force changes its
course
• fall to the ground because of
gravitational pull

Answers

Answer:

Accelerate according to the applied force.

Explanation:

According to Newton's second law of motion, a force applied on a body produces acceleration in its own direction. Therefore, if you hit a baseball with a bat it will accelerate according to the applied force.

Answer:

Explanation:

Given:

m -  Baseball mass

F - Force applied from the side of the bat to the baseball

_________________________

a - ?

2 Newton's law:

a = F / m

Correct answer:

Accelerate according to the applied force

Which is phrase is an example of kinetic energy

Answers

The phrase "energy that a ball has and produces as it rolls down a hill"  is an example of kinetic energy.

What is kinetic energy?

Kinetic energy is a type of energy that a particle or an object possesses as a result of its motion. By exerting a net force on an object, work is done, which transfers energy; as a result, the object accelerates and gains kinetic energy.

A moving object or particle's ability to move depends on both its mass and motion. This is known as kinetic energy. Translation (or movement along a path from one place to another), rotation about an axis, vibration, or any combination of motions are examples of possible types of motion.

A body's squared translational kinetic energy, or 1/2mv², is equal to one-half the product of its mass, m, and its velocity, v.

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some of the plans to restore the everglades will require millions of dollars and would negatively affect local farmers. what information would you consider in deciding what should be done?

Answers

The information which would be considered in deciding what should be done in restoring everglades is the cost, terrain and environmental effects.

What is Everglade?

This is referred to a natural region of tropical wetlands which can be found in the southern region of the U.S. state of Florida. It is home to a lot of organisms ranging from plants to animals which ensures that they survive the various conditions due to the availability of nutrients etc.

The information which would be considered in deciding what should be done in restoring everglades is the cost as a cheap reliable method is preferable and also the effect on the environment as a whole.

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i’m willing to give anybody extra points plus brainliest if anybody is willing to help me with this. please help!! this is due soon.

Answers

1. The box will move to the right with a force of 50 N when a 75 N force is applied to the left.

2. The box will not move if a 50 N force us applied to the left.

For  Balanced, B or Unbalanced forces, U the correct option are:

B A person jogging at a constant speedU  A car accelerating at a green light.U Pushing a lawnmower across the yardB A cookie sitting on a plate.U Slowing down to stop at a red light.U A bowling ball knocking over pins.B A book sitting on a shelf.U A linebacker tackling a running back.B A person sitting on a chair.B A plane flying at a constant speed.

What are balanced and unbalanced?

Balanced forces are forces that do not produce an acceleration of an object. Net force will be zero.

Unbalanced forces are forces that produce an acceleration of a body. Net force will be greater than zero.

Considering the boxes:

1. Net force = 50 N

Forces to the left = 25 N + x

Forces to the right = 50 N

Net force = Force to the left + force to the right

50 N = 25 N + x - 50

x = 75 N

2. Net force = 0 N

Forces to the left = 75 N + x

Forces to the right = 125 N

Net force = Force to the left + force to the right

0 N = 75 N + x -125

x = 50 N

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A motor car having a mass of 2 tonnes is being accelerated up a gradient of 1 in 25. At an engine speed of 4 000 rimin the b. P. Is 57 kw the effective tyre radius is 330 mm, the rolling res?stance is 180 n/tonne, and the rear-axle ratio is 4. 4 to 1 assuming a transmission efficiency of 90 % and neglecting air res?stance, determine the value of the acceleration at the given speed 262 mls1.

Answers

The value of the acceleration at the given speed is  0.26333 m/s²

Acceleration is the price of the alternate speed of an object with admire to time. Accelerations are vector quantities. The orientation of an item's acceleration is given via the orientation of the net force appearing on that item.

Acceleration is the rate at which pace adjustments with time, in phrases of both velocity and path. A point or an item shifting in a direct line is extended if it accelerates or slows down. movement on a circle is extended despite the fact that the rate is constant because the route is usually changing.

Given,

mass of car = 2 tones

                    = 2000 kg

power transfer of wheel = efficiency × bp

P = 0.9 × 57000

P = 51300 W

Acceleration:-

Net force = mass × acceleration

2000 × a = F - ( Fr - Fg)

2000a = 1670.0418 - ( 360v+ 783.37)

Acceleration =  0.26333 m/s²

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L Pretest: Unit 4Question 7 of 22What is the wavelength of an electromagnetic wave that has a frequency of1.82 x 10^18 Hz in a vacuum? (The speed of light in a vacuum is 3.00 x 10^8m/s.)A. 1.65 x 10-10 mB. 5.46 x 1026 mC. 6.07 x 109 m

Answers

Answer:

A. 1.65 x 10^-10 m

Explanations:

The relationship between the speed(v), frequency(f), and wavelength(λ) of an electromagnetic wave is given as:

v = λf

From the question:

[tex]\begin{gathered} v\text{ = 3}\times10^8m\text{ /s} \\ f\text{ = 1.82}\times10^{18}Hz \end{gathered}[/tex]

Substituting the values of v and f into the equation v = λf

[tex]\begin{gathered} 3\times10^8=\lambda\times(1.82\times10^{18}) \\ \lambda\text{ = }\frac{3\times10^8}{1.82\times10^{18}} \\ \lambda\text{ = }1.65\text{ }\times10^{-10}m \end{gathered}[/tex]

Therefore, the wavelength of the electromagnetic wave is 1.65 x 10^-10 m

what will the killograms be of 981N and 160N

Answers

The mass of the objects in kilograms could be obtained as;  100 Kg and  16.3 Kg.

What is weight?

The term weight has to do with the effect of the gravitational force on an object hat is found on the surface of the earth. Note that the weight is a force an d the direction of the weight must always be towards the center of the earth.

Now we are asked to convert 981N and 160N to kilograms. Recall that the weight is the product of the mass of the object in kilograms to the acceleration due to gravity.

Mass = weight/acceleration due to gravity

1)  981N/9.8 m/s^2

= 100 Kg

2) 160N/9.8 m/s^2

= 16.3 Kg

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Use your periodic table to determine the following information
about the element Sulfur (S).
a. Number of protons =
b. Number of electrons =
c. Number of neutrons =

Answers

Unless otherwise specified as an ion, protons = electrons

Atomic number = number of protons
Atomic weight/mass = protons + neutrons

Protons : 16
Electrons: 16

Neutrons = Weight-Atomic number = 32-16 = 16

A spring with a spring of 4.75n/m applies a force of 3.25N when it is stretched. How much was the spring compressed

Answers

Answer:

The spring was compressed by 0.684 m

Explanation:

Soring constant, k = 4.75

The applied force, F = 3.25 N

Note that spring will compress back by the same distance it expands

Compression, x = ?

Using the equation F = kx

3.25 = 4.75x

x = 3.25/4.75

x = 0.684 m

The spring was compressed by 0.684 m

What type of energy is the sum of kinetic and potential energy in an object that is used to do work?.

Answers

Mechanical energy can be described as a sum of kinetic and potential energy in an object that is used to do work

In the field of physics, we can describe mechanical energy that is either stored in an object at the time of rest or the energy of an object that is in a particular motion. As kinetic energy is the motion or movement energy and potential energy is the stored energy at rest, hence mechanical energy is the sum of both these energies.

In other words, we can also describe mechanical energy as an energy that is contained in a particular object that allows it to perform a specific work. It depends on the mechanical energy of an object to determine the amount of work it can do.

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Answer:

mechanical energy or A

Explanation:

Hope this helps

If you were walking your dog and started at A went to B then to C and finally returned to A what would your speed be if it took you 5 seconds, what would
your velocity be?

Answers

Answer:

Speed 5 m/s , velocity 0 m/s

Explanation:

s= d/t = 25/5 = 5 m/s

υ= Δx/Δt = 0/5 = 0 m/s

A 0.0254 m long magnet is held next toa wire carrying 0.530 A of current, sothat the field is perpendicular to the wire.The resulting magnetic force is3.67*10^-4 N. What is the strength ofthe field?(Unit = T)Magnetic Field (T)

Answers

The force of a magentic field is given by the next formula

[tex]F=IBL\cdot sin(\theta)[/tex]

We have F force, I current, B magnetic field, L lenght and sin theta which represents the angle between them. This is important because this interactions depends on the direction.

[tex]\begin{gathered} B=\frac{F}{IL\cdot sin(\theta)} \\ B=\frac{3.67\cdot10^{-4}N}{0.0254m\cdot0.53A\cdot sin(90)} \\ B=0.027T \end{gathered}[/tex]

Based on the information, the angle is 90 because is perpendicular, as it is mentioned on the text

Answer questions on redox reactions och of the following chemical reactions, identify the chemical that is used and the chemical that is reduced. Give a reason for your answer. identify the oxidising and reducing agents. 4Na+O2->2Na2O

Answers

The reducing agent in the reaction is Sodium and the oxidizing agent in the reaction is oxygen.

The provided chemical reaction is,

4Na+O₂ → 2Na₂O

Oxidation is the process of addition of oxygen or the removal of electrons from the product. Oxidation number increases in this case. Compound which undergoes reduction is called oxidizing agent.

Reduction is the process of removal of oxygen or the addition of electrons from the product. Oxidation number decreases in this case. compound which undergoes oxidation is called reducing agent.

In the reaction,

Oxygen is added to Na. So, Na is oxidized, hence it is the reducing agent and Oxygen is getting reduced, so, it is the oxidizing agent.

Reducing agent → Na.

Oxidizing agent → O₂.

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how much time will it take a dog to run 15 meters if its running 5m/s

Answers

Uniform line movement

Data:

t = ?

d = 5 mt

V = 15 m/s

The rectilinear movement formula:

     V = d/t

We clear for time t:

     t = d/v

     t = (15 m)/(5 m/s)

     t = 3 s

Answer: The dog takes 3 seconds to travel 15 meters ✅.

¿What is the MRU?

The MRU is defined as the movement in which an object moves in a straight line, in a single direction, covering equal distances in the same time interval, maintaining a constant speed and no acceleration throughout its movement.

His formula for uniform rectilinear motion is as follows:

V = D/T

We first apply the data to the problem.

Data :T = ?D = 5 metersV = 15 m/s

Once having the data Now we will find the time.

T = D/VT = (15 meters)/(5 m/s)T = 3 seconds

So the result of the problem is 3 seconds.

Happy 2023.

if the air inside the warehouse is at a warm while the outside air is a chilly and each friend is standing from the person in the doorway, what is the time difference between the arrival

Answers

The time difference between the arrival of the sound at the two friends is 27.4 milliseconds

In getting the difference between the arrival of the sound at the two friends, we first find the following:

Speed of sound at [tex]26.1^{o} C[/tex](v1):

[tex]v1=331*\sqrt{\frac{26.1+273K}{273K} }[/tex]

v1=346.5m/s

Speed of sound at [tex]-22.2^{o} C[/tex](v2):

[tex]v2=331*\sqrt{\frac{-22.2+273K}{273K} }[/tex]

v2=317.3m/s

The time difference:

Change in time, Δt=(d/v2)-(d/v1), where d=103m

Change in time=(103/317.3)-(103/346.5)

                      Δt=27.4ms

Change in time=27.4milliseconds

The question was incomplete, complete question is given below:

If the air inside the warehouse is at a warm 26.1​*​​C while the outside air is a chilly -22.2​*​​C, and each friend is standing 103 meters from the person in the doorway, then what is the time difference between the arrival of the sound at the two friends? Give your answer as a positive value in milliseconds

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1. What is the speed of a rocket that travels 900 meters in 10.2 seconds?

Answers

Speed is a scalar quantity which only has magnitude but lack of direction. Speed is the distance that an object travels divided by the time it takes. Therefore we can mathematically express as:

[tex]\displaystyle v=\dfrac{s}{t}[/tex]

Where v is speed, s is distance and t is time. From the problem, we are given the distance equal 900 meters and time it takes is 10.2 seconds. Therefore substitute s = 900 meters and t = 10.2 seconds.

[tex]\displaystyle{v=\dfrac{900 \ \, \sf{meters}}{10.2 \ \, \sf{seconds}}}\\\\\displaystyle{v=88.24 \ \, \sf{m/s}}[/tex]

Therefore, the speed of rocket is 88.24 m/s or 90 m/s when rounding to one significant figure.

a 2,100-kg car moving east at 10.0 m/s collides with a 3,000-kg car moving north. the cars stick together and move as a unit after the collision, at an angle of 33.0° north of east and at a speed of 4.91 m/s. find the speed of the 3,000-kg car before the collision.

Answers

The initial velocity of the car with the mass of 3000kg before the inelastic collision is 1.347m/s.

What is Collision?

For two objects, the relative speed between them equals the change in distance between them divided by the change in time.

In an inelastic collision, the momentum of the bodies remain constant even after collision. This works on the principle of conservation of momentum.

p = m.v

where, p = momentum of the body,

m = mass of the body,

v = velocity of the body

Here,

m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂

Therefore, the velocity of 3000kg car (m₂) can be calculated by this formula:

m₁ = 2100 kg

u₁ = 10m/s

m₂ = 3000kg

u₂ = ?

v₁ = v₂ = 4.91 m/s

Therefore,

m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂

(2100kg × 10) + (3000 × u₂) = (2100 × 4.91) + (3000 ×4.91)

21000 + 3000u₂ = 10,311 + 14730

3000u₂ = (10311+14730) - 21000

3000u₂ = 25041 - 21000

3000u₂ = 4041

u₂ = 4041/3000

u₂ = 1.347m/s

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a block slides to the right with speed v on a frictionless floor and collides with a bigger block which is initially at rest. after the collision the speed of both blocks is v/3 in opposite directions. 1)was the collision elastic?

Answers

We can see that the collision of the objects is an elastic collision.

What is the kind of collision?

Let us note that a collision could be elastic or in elastic. We can say that a Collison could be judged or said or designated to be an elastic collision when the kinetic energy and the momentum of the system that is undergoing the collision is conserved.

Let us recall that the principle of the conservation of the linear momentum states that the momentum before collision is equal to the total momentum after Collison. In other words, the momentum of the system does not change. Hence, the momentum of one of the objects must be transferred to the other object when they collide in a closed system

With that said, we can see that the two bocks move in opposite directions thus it is an elastic collision as we can see from the description in this answer.

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1. A skydiver jumps out of a plane and is in freefall. What is their acceleration?

Answers

If a skydiver jumps out of a plane and is in freefall, then his acceleration would be 9.8 meters / second².

What is gravity?

It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.

As given in the problem statement if a skydiver jumps out of a plane and is in freefall, the acceleration due to gravity would be 9.8 meters / second².

Thus, if a skydiver jumps out of a plane and is in freefall, then its acceleration due to gravity would be 9.8 meters / second².

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the most likely places where stars and planetary systems are forming in the universe are- the most likely places where stars and planetary systems are forming in the universe are- in nebulae composed of gas and dust. in regions surrounding quasars. in the rarified space between galaxies. in the centers of galaxies.

Answers

The most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

Stars are massive, hot, luminous bodies of gas that emit large amounts of radiation and derive their energy from nuclear fusion. A planetary system comprises of a star and all the objects that revolve around it.

Stars are born in nebulae. They are a cluster of gas and dust scattered throughout a galaxy. Gravitational attraction between the gas and dust particles causes turbulence, which gives rise to knots. When these knots acquire sufficient mass, they collapse, and when the reach a certain temperature, nuclear fusion of hydrogen atoms into helium atoms begins. At this point, star has been born.

Planets can be said to be formed as a by-product of star formation, through a process called accretion. Smaller objects stick together through gravity, forming bigger objects. Gravitational pull from the nearby star and the object's own momentum causes the object to revolve round the star. At this point, a planet has been born.

Thus, the most likely places where stars and planetary systems are forming in the universe are in nebulae composed of gas and dust.

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A car with a mass of 1500 kg travelling at 5m / s is accelerated for 10.0 s to a speed of 25m / s What force was required? The coefficient of rolling kinetic friction was 0.009.

Answers

Answer:

Force:

F = 3130 N

Explanation:

Given:

m = 1500 kg

V₀ = 5 m/s

V = 25 m/s

Δt = 10.0 s

μ = 0.009

g = 9.8 m/s²

___________

F - ?

1)

Car acceleration:

a = (V - V₀) / Δt = (25 - 5) / 10.0 = 2 m/s²

2)

Friction force:

F₁ = μ*m*g

3)

According to Newton's second law:

m*a  = F - F₁

Force:

F = m*a + F₁

F = m*a + μ*m*g

F = m*( a + μ*g) = 1500*(2 + 0.009*9.8) ≈ 3130 N

If you have two different sized velocity vectors representing two objects moving in the same direction, then what can you conclude? a. Their magnitudes are the same. c. One object has a greater velocity then the other. b. Their magnitudes are different. d. Both B and C.

Answers

If you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.

A velocity vector is the rate of change of an object's position. A velocity vector has both magnitude and direction. The magnitude of the velocity vector gives the speed of the object while the direction of the vector gives the direction of the object's velocity.

If a vector's size is longer than the other, it means that the vector has a magnitude higher than the other. If the magnitude is higher, the velocity will be higher.

Therefore, if you have two different sized velocity vectors representing two objects moving in the same direction, then you can conclude both B and C are correct.

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a hawk flies in a horizontal arc of radius 10.3 m at a constant speed of 4.8 m/s. find its centripetal acceleration. answer in units of m/s 2 . 013 (part 2 of 2) 10.0 points it continues to fly along the same horizontal arc but increases its speed at the rate of 0.63 m/s 2 . find the magnitude of acceleration under these new conditions. answer in units of m/s 2 .

Answers

The hawk’s centripetal acceleration is 2.23 m/s²

The magnitude of the acceleration under new conditions is 2.316 m/s²

radius of the horizontal arc = 10.3 m

the initial constant speed = 4.8 m/s

we know that the centripetal acceleration is given by

    [tex]a_{c}[/tex]  = [tex]\frac{v^{2} }{r}[/tex]

   [tex]a_{c}[/tex]  = 23.04/10.3

    [tex]a_{c}[/tex]  = 2.23 m/s²

It continues to fly but now with some tangential acceleration

[tex]a_{t}[/tex] = 0.63 m/s²

therefore the net value of acceleration is given by the resultant of the centripetal acceleration and the tangential acceleration

so

[tex]a_{net}[/tex]  =  [tex]\sqrt{a_{c} ^{2} +a_{t} ^{2} }[/tex]

[tex]a_{net}[/tex]  =  [tex]\sqrt{4.97 + 0.396}[/tex]

[tex]a_{net}[/tex]  =  2.316 m/s²

So the magnitude of  net acceleration will become 2.316 m/s².

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A body is under the action of two forces 7n and 10n. find the resultant of the two forces if the two are inclined at an angle of 60degrees to each other

Answers

Mass x Acceleration equals force. Net force is equal to 7N plus 10N, or 17N, at a 60-degree angle with R equal to 12.2N.

How does physics define force?

The definition of force in physics is: The push and pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A force is an effect that tends to move a stationary object into motion, stop a moving object, alter the direction and speed of a moving object, or alter the size and shape of a body.

Which four sorts of forces are there?

Any of the four fundamental forces in physics—gravitational, electromagnetism, strong, and weak—that control how objects and particles interact as well as how some particles decay—is referred to as a fundamental force or fundamental interaction.

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A train begins to slow down at a rate of -2.5 m/s2 and it takes 137 seconds to come to a complete stop. How fast was the train going when it started to slow down?

Answers

The train was moving with a velocity of 342.5 m/s when it started to slow down

How do I determine the initial velocity of the train?

From the question given above, the following data were obtained:

Deceleration (a) = -2.5 m/s²Time (t) = 137 secondsFinal velocity (v) = 0 m/sInitial velocity (u) = ?

Considering the above data, we can obtain the initial velocity of the train as follow:

v = u + at

0 = u + (-2.5 × 137)

0 = u - 342.5

Collect like terms

u = 0 + 342.5

u = 342.5 m/s

Thus, from the above calculation, we can say that the train was moving with a velocity of 342.5 m/s

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a pickup truck, carrying a box on a level road, accelerates forward from a stoplight. assuming that the box does not slide on the bed of the truck, as the truck is accelerating forward, the frictional force exerted on the box by the bed of the truck is in which direction?

Answers

The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it. The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward.

As long as the crate accelerates at the same rate as the truck, it won't slide. The static frictional force therefore contributes to the net force that must act on the crate in order to accelerate it.

The static frictional force is directed forward, up the hill, because the crate has a tendency to slide backward. To cause a commensurate rise in the crate's acceleration, the truck's acceleration must likewise increase.

However, the static frictional force can only build up to a certain point, after which the crate and vehicle will accelerate to their maximum rate. The crate will slip if the acceleration is raised much further.

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A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i. What is the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy ?.

Answers

A person with moment of inertia i is spinning at an angular velocity ω. At some point in time he moves his arm position such that his moment of inertia changes to 2i.  the rotational kinetic energy k of the person after the change, in terms of his initial rotational kinetic energy is 1/4 .

The moment of inertia of a rigid body, also referred to as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. The amount of torque required to modify the body's rate of rotation depends on the mass distribution of the body and the axis selected. For example, larger moments require more torque.

The moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. This is an extensive (additive) property.

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Alyssa mixed 12 mL of a salt solution with 9mL of a 39% salt solution, to make a 56% salt solution. Find the percent salt concentration of the first solution.

Answers

Alyssa mixed 12 mL of a salt solution with 9mL of a 39% salt solution, to make a 56% salt solution. The percent salt concentration of the first solution will be 78.08 %.

An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.)

let x = percentage of 12ml of solution

12x + 0.39 (9) = 0.56 (12 + 11)

12x + 3.51 = 12.88

x = 0.7808

The percent salt concentration of the first solution will be 78.08 %

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